抱歉,您的浏览器无法访问本站

本页面需要浏览器支持(启用)JavaScript


了解详情 >

blaire

👩🏻‍💻ブレア🥣

image

其中重点为:1/2/5/6/7/10/11/12/13/15/17/18/19/22/23/25/31/35/36/40/41/42/45/46 共16题

超级重点 18和23、 22和25 、 41、46

(1). 查询课程编号为“01”的课程比“02”的课程成绩高的所有学生的学号(重点)

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
SELECT
t1.s_id as t1_s_id,
t2.s_id as t2_s_id,
t3.s_name,
t1.s_score as s_score_01,
t2.s_score as s_score_02
FROM
(select s_id, c_id, s_score from Score WHERE c_id = '01') as t1
INNER JOIN
(select s_id, c_id, s_score from Score WHERE c_id = '02') as t2
ON t1.s_id = t2.s_id
INNER JOIN
Student as t3
ON t1.s_id = t3.s_id
where t1.s_score > t2.s_score

DISTINCT

1
2
3
4
5
6
SELECT DISTINCT column1, column2, ...
FROM table_name;

SELECT column1, column2, ...
FROM table_name
WHERE condition1 AND condition2 AND condition3 ...;
1
2
3
4
5
6
INSERT INTO table_name (column1, column2, column3, ...)
VALUES (value1, value2, value3, ...);

SELECT MIN(column_name), MAX(column_name), COUNT, AVG, SUM
FROM table_name
WHERE condition;

BETWEEN … AND

1
2
3
4
5
6
7
8
9
10
11
12
SELECT column_name(s)
FROM table_name
WHERE column_name BETWEEN value1 AND value2;

SELECT *
FROM Orders
LEFT JOIN Customers

SELECT column_name(s)
FROM table1
INNER JOIN table2
ON table1.column_name = table2.column_name;

HAVING

1
2
3
4
SELECT COUNT(CustomerID), Country
FROM Customers
GROUP BY Country
HAVING COUNT(CustomerID) > 5;

UNION

1
2
3
4
SELECT City FROM Customers
UNION
SELECT City FROM Suppliers
ORDER BY City;

Comments